Nicholas Jamieson
1 min readSep 6, 2018

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No, the static pipe has been there from the outset. It’s included so that operators can be composed independently of their application to an observable.

The pipe method won’t be changing and its overload signatures are not going to be removed.

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Nicholas Jamieson
Nicholas Jamieson

Written by Nicholas Jamieson

RxJS core team member; front-end developer; mentor; speaker; open-source contributor

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