Nicholas Jamieson
1 min readFeb 6, 2018

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That’s right. The operator is not exported as — nor called using — a symbol, so the bundler cannot reliably determine whether or where it’s called. For example, it could be called like this someObservable[someVariable](value => value) where someVariable just happens to be "map".

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Nicholas Jamieson
Nicholas Jamieson

Written by Nicholas Jamieson

RxJS core team member; front-end developer; mentor; speaker; open-source contributor

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